CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Transmission of Wave

16.In a YDSE ...

Question

16.In a YDSE , bichromatic light wavelength 400 nm and 560 nm are used . The distance between the slits is equal to 0.1 millimetre and the distance between the plane of the slit and the screen is 1m . Find the minimum distance between the two successive region of complete darkness.

Open in App

Solution

Suggest Corrections

thumbs-up

10

Similar questions

YDSE

, dichromatic light of wavelengths

400 nm

560 nm

are used. The distance between the slits is

0.1 mm

and the distance between the plane of the slits and the screen is

1 m

. The minimum distance between two successive regions of complete darkness is

Q. In YDSE, bichromatic light of wavelengths

400 nm

560 nm

are used. The distance between the slits is

0.1 mm

and the distance between the plane of the slits and the screen is

1 m

. The distance of the second region of complete darkness from central maximum is :

Q. In a YDSE bichromatic light of wavelength

400 n m

560 n m

are used. The distance between the slits is

0.1 m m

and the distance between the plane of the slits and the screen is

1 m

. The minimum distance between two successive regions of complete darkness is

Q. Monochromatic light of wavelength

400 n m

560 n m

are incident simultaneously and normally on double slits apparatus whose slits separation is

0.1 m m

and screen distance is

1 m

. Distance between areas of total darkness will be:

Q. Monochromatic light of wavelength

400

560

nm are incident simultaneously and normally on double slits apparatus whose slits separation is

0.1

mm and screen distance is 1m. Distance between areas of total darkness will be

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Wave Reflection and Transmission

PHYSICS

Watch in App

explore_more_icon

Explore more

Transmission of Wave

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon