Question

$16men$ can do a peice of work in $48days$. How many will be required to do the work in $24days$.

Answer 1

No. of men $\propto \frac{1}{No.ofdays}$

$\Rightarrow$ (No. of men)(No. of days)$=$ constant

$\Rightarrow 16\times 48=$ constant

Let x be the no. of men

$\Rightarrow x\times 24=$ constant

$x\times 24=48\times 16$

$x=\frac{48\times 16}{24}$

$x=32$ men.