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Characteristics of Chemical Equilibrium

16 moles of H...

Question

16 moles of $H_{2}$ and 4 moles of $N_{2}$ are sealed in a one litre vessel. The vessel is heated at a constnat temperature until the equilibrium is established, it is found that the pressure in the vessel has fallen to 9/10 of its original value. Calculate newly concentration of $N_{2}$ and $N H_{3}$ in $m o l L^{- 1}$
$N_{2 (g)} + 3 H_{2 (g)} ⇌ 2 N H_{3 (g)}$

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Solution

The given equilibrium is
$\begin{matrix} N_{2} (g) & + & 3 H_{2} (g) & ⇌ & 2 N H_{3} (g) A t t = 0 & 4 & 16 & 0 A t e q u i l i b r i u m & 4 - x & 16 - 3 x 2 x \end{matrix}$
Total gaseous moles at equilibrium $= 4 - x + 16 - 3 x + 2 x = (20 - 2 x)$
Since, pressure has fallen to 9/10 of its original value, hence no. of mole will also fall up to the same extent.
$(20 - 2 x) = \frac{9}{10} \times 20 = 18$
$x = 1$
$[N_{2}] = \frac{4 - x}{1} = \frac{4 - 1}{1} = 3 m o l e / l i t r e$
$[N H_{3}] = \frac{2 x}{1} = 2 m o l e / l i t r e$

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Characteristics of Chemical Equilibrium

Standard XII Chemistry

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