CameraIcon

SearchIcon

MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Cube Root

16. Prove tha...

Question

16. Prove that root 7 is not a cube of rational number

Open in App

Solution

Suggest Corrections

thumbs-up

12

Similar questions

Proof that 7+root5 is not a rational number.

\sqrt{5} - \sqrt{3}

is not a rational number.

\sqrt{5}

is not a rational number. Hence, prove that 2 -

\sqrt{5}

is also irrational.

a, b, c, p

be rational numbers such that

p

is not a perfect cube.

a + b p^{\frac{1}{3}} + c p^{\frac{2}{3}} = 0

, then prove that

a = b = c = 0

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Cube Root

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon