16th term in the expansion of -x-y17 isA- 136 x y7B- 136 x yC- -136 x y15 - 2D- -136 x y2

The correct option is C T_16 = nbsp;^17 nbsp;C nbsp;_15 nbsp;(√(x))^2 ( √(y))^15 = nbsp; 17×16/2×1 nbsp;× xy ^ 15/2 nbsp;= 136 xy^ 15/2 ...

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Middle Terms

16th term in ...

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$16^{t h}$ term in the expansion of $(\sqrt{x} - \sqrt{y})^{17}$ is

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