16. 'X' AND 'Y' ARE OXYANION OF Cr . 'X' IN PRESENCE OF H+ GIVES 'Y' 'Y' IN PRESENCE OF OH- GIVES 'X' 'Y' IN PRESENCE OF SO2 GIVES 'Z' & SO4(-2) FIND OXIDATION STATE OF Cr IN 'X','Y','Z'. RESPECTIVELY 1. +3,+6,+6 2.+6,+3,+6 3.+6,+6,+6 4.+6,+6,+3

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Δ_{1} = ∣ ∣ ∣ ∣ ∣ \begin{matrix} y^{5} z^{6} (z^{3} - y^{3}) & x^{4} z^{6} (x^{3} - z^{3}) & x^{4} y^{5} (y^{3} - x^{3}) y^{2} z^{3} (y^{6} - z^{6}) & x z^{3} (z^{6} - x^{6}) & x y^{2} (x^{6} - y^{6}) y^{2} z^{3} (z^{3} - y^{3}) & x z^{3} (x^{3} - z^{3}) & x y^{2} (y^{3} - x^{3}) \end{matrix} ∣ ∣ ∣ ∣ ∣

and

Δ_{2} = ∣ ∣ ∣ ∣ ∣ \begin{matrix} x & y^{2} & z^{3} x^{4} & y^{5} & z^{6} x^{7} & y^{8} & z^{9} \end{matrix} ∣ ∣ ∣ ∣ ∣

. then

Δ_{1}

is equal to

Q. '6 decreased by 2x and gives 3y' can be algebraically written as______.

Q. If

x, y, z

are in A.P. and

{tan}^{- 1} x, {tan}^{- 1} y, {tan}^{- 1} z

are also in A.P., then

Division of $72 x^{2}$ $y^{4}$ $z^{6}$ by $8 x^{2}$ $y^{2}$ $z^{3}$ gives $9 y^{2}$ $z^{3}$ .

A neutral organic compound X of molecular formula $C_{2} H_{6} O$ on oxidation with acidified potassium dichromate gives an acidic compound Y. Compound X reacts with Y on warming in the presence of conc. $H_{2} S O_{4}$ to give a sweet-smelling substance Z. What are X, Y and Z?

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