Question

16g of oxygen and 3g of hydrogen are present in a vessel at $0^{0}C$ and 760mm of Hg pressure.Volume of the vessel is:

• A. 22.4L
• B. 44.8L
• C. 11.2L
• D. 5.6L

Answer 1

Answer: (B)

44.8L

Moles of oxygen is $1/2$ as $\frac{16}{32}$ and mole of hydrogen is $\frac{3}{2}$.

Therefore total moles is $\frac{1}{2}+\frac{3}{2}=2$

Using,

$PV=nRT$ $P=760mm=1ATM$

$\Rightarrow V=\frac{nRT}{P}$ $T=273K$

$\Rightarrow V=\frac{2\times 0.0821\times 273}{1}$ $R=0.0821$

$\Rightarrow V=44.851lit$ $n=2$