$16 g$ of oxygen occupy $0.025 m^{2}$ at $27^{o} C$ . If the universal gas constant is $8.4 J . m o l e$ $K$ . Find the pressure exerted by it. (molecular weight of oxygen is $32 a . m . u$ )

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Solution

Given : Mass of gas $m = 16 g$
Molar mass $M = 32$
Gas constant $R = 8.4 \frac{J m o l e^{- 1}}{K}$
Volume $= 0.025 m^{3}$
$\Rightarrow$ According to $P V = n R T$
$\Rightarrow P V = \frac{m}{M} R T$
$\Rightarrow P = \frac{16 \times 8.4 \times 300}{32 \times 0.025}$
$\Rightarrow P = 50, 400 N m^{- 2}$
$= 0.5 a t m$
Hence, the answer is $0.5 a t m$

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16g of oxygen occupy 0.025m2 at 27oC. If the universal gas constant is 8.4J.mole K. Find the pressure exerted by it. (molecular weight of oxygen is 32a.m.u)

Given : Mass of gas m=16g Molar mass M=32 Gas constant R=8.4Jmole−1K Volume =0.025m3⇒ According to PV=nRT⇒PV=mMRT⇒P=16×8.4×30032×0.025⇒P=50,400Nm−2 =0.5atmHence, the answer is 0.5atm

$16 g$ of oxygen occupy $0.025 m^{2}$ at $27^{o} C$ . If the universal gas constant is $8.4 J . m o l e$ $K$ . Find the pressure exerted by it. (molecular weight of oxygen is $32 a . m . u$ )