Question

16x-10/x=27 find root

Answer 1

Dear Student,
$$\begin{gathered} 16x-\frac{10}{x}=27 \\ \Rightarrow \frac{16x^2-10}{x}=27 \\ \Rightarrow 16x^2-10=27x \\ \Rightarrow 16x^2-27x-10=0 \\ \Rightarrow 16x^2-32x+5x-10=0 \\ \Rightarrow 16x\left(x-2\right)+5\left(x-2\right)=0 \\ \Rightarrow \left(16x+5\right)\left(x-2\right)=0 \\ \Rightarrow \mathit{x}\mathbf{=}\frac{\mathbf{-}\mathbf{5}}{\mathbf{16}}\mathbf{}\mathbf{,}\mathbf{}\mathbf{2} \end{gathered}$$
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