Factorisation of Algebraic Expressions Using Identities
16x^5 - 144x^...
Question
16x5−144x3 =
A
16x3(x−3)(x−3)
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B
16x5(1−9x2)
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C
16x3(3+x)(3−x)
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D
16x3(x+3)(x−3)
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Solution
The correct option is D16x3(x+3)(x−3) The given expression 16x5−144x3 can be written as, 16x3×x2−16×9×x3 = 16x3×x2−16x3×9 = 16x3(x2−9) = 16x3(x2−32) Using the identity : a2−b2=(a+b)(a−b), we get, 16x3(x+3)(x−3)