Question
17. A 10 g mixture of Cu2S and CuS was treated with 200 ml of 0.75 M MnO4 in acid solution producing SO2, Cu22+ and Mn2+. The SO2 was boiled off and the excess MnO4 was titrated with 175 mL of 1 M Fe2+ solution. Calculate the percentage of CuS in the original solution Options: 42.6% 57.4% 27.6% 72.4%