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Question

17cards numbered 1,2,3,,16,17 are put in a box and mixed thoroughly. One person draws a card from the box. Find the probability that the number on the card is (i) odd (ii) a prime (iii) divisible by 3 (iv) divisible by 3 and 2 both.


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Solution

Step 1: Find the probability that the number on the card is odd:

The seventeen cards are numbered from 1,2,3,...16,17

The odd numbers in the cards are 1,3,5,7,9,11,13,15,17

Thus, the number of favorable outcomes for the given event is 9

The formula for probability will be,

Probability=NumberoffavorableoutcomesTotalnumberofoutcomes

Thus, the probability will be,

Probability=917

Step 2: Find the probability that the number on the card is prime:

The seventeen cards are numbered from 1,2,3,...16,17

The prime numbers in the cards are 2,3,5,7,11,13,17

Thus, the number of favorable outcomes for the given event is 7

The formula for probability will be,

Probability=NumberoffavorableoutcomesTotalnumberofoutcomes

Thus, the probability will be,

Probability=717

Step 3: Find the probability that the number on the card is divisible by 3:

The seventeen cards are numbered from 1,2,3,...16,17

The numbers in the cards which are divisible by three are 3,6,9,12,15

Thus, the number of favorable outcomes for the given event is 5

The formula for probability will be,

Probability=NumberoffavorableoutcomesTotalnumberofoutcomes

Thus, the probability will be,

Probability=517

Step 4: Find the probability that the number on the card is divisible by 3 and 2 both:

The seventeen cards are numbered from 1,2,3,...16,17

The numbers in the cards which are divisible by three and two both are 6,12

Thus, the number of favorable outcomes for the given event is 2

The formula for probability will be,

Probability=NumberoffavorableoutcomesTotalnumberofoutcomes

Thus, the probability will be,

Probability=217

Hence, the probability that the number on the card is

(i) odd =917

(ii) a prime =717

(iii) divisible by 3 =517

(iv) divisible by 3 and 2 both=217


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