17. How to solve log5 +log6

Open in App

Solution

Suggest Corrections

Similar questions

{log}_{5} x {log}_{6} x {log}_{7} x = {log}_{5} x . {log}_{6} x + {log}_{6} x . {log}_{7} x + {log}_{7} x . {log}_{5} x

{log}_{3} 108, {log}_{4} 192, {log}_{5} 500, {log}_{6} 1080

{log}_{3} 2 \times {log}_{4} 3 \times {log}_{5} 4 \times {log}_{6} 5 \times {log}_{7} 6 \times {log}_{8} 7 = \frac{1}{3}

l o g (6 / x) > l o g (x + 5) .

{log}_{02} {log}_{6} (\frac{x^{2} - x}{x^{2} + x}) > 0

Join BYJU'S Learning Program