$18^{3}$ can be written as

9^{3} \times 9^{3}

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2^{3} \times 3^{3} \times 3^{3}

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3^{3} \times 3^{3} \times 3^{3}

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9^{3} \times 3^{3}

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Solution

The correct option is B $2^{3} \times 3^{3} \times 3^{3}$
The prime factors of $18$ are $2, 3$ and $3$
$\Rightarrow 18 = 2 \times 3 \times 3 \Rightarrow 18^{3} = 2^{3} \times 3^{3} \times 3^{3}$

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