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18.An object ...

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18.An object is given at initial velocity of 25/4 m/s and then it is decelerated at a rate given by dv/dt=-5/2v in si units. the time taken by paricle to come to rest is

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Q. An object, moving with a speed

6.25 m s^{- 1}

, is decelerated at a rate given by

\frac{d v}{d t} = - 2.5 \sqrt{v}

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is intantaneous velocity. The time taken by the object to come to rest would be:

Q. An object,moving with a speed of

6.25 m s^{- 1}

, is decelerated at a rate given by

d v / d t = - 2.5 (v)^{0.5}

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Q. An object moving with a speed of

6.25

m/s, is decelerated at a rate given by

\frac{d v}{d t} = - 2.5 \sqrt{v}

v

is the instantaneous speed. The time taken by the object, to come to rest, would be then

Q. An object moving with an speed of 25 m/s is decelerating at a rate given by

a = - 5 \sqrt{v}

, where v is speed at any time. The time taken by the object to come to rest is:

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