Question

18) Deuteron and $\alpha$ - particle are put 1A$°$ apart in All magnitude of intensity of electric field due to deuteron at $\alpha -particle$ is (N/C).
$$\begin{gathered} 1)Zero \\ 2)2.88\times {10}^{11} \\ 3)1.44\times {10}^{11} \\ 4)5.76\times {10}^{11} \end{gathered}$$

Answer 1

Dear student
$$\begin{gathered} E=\frac{kq}{r^2}=\frac{9\times {10}^9\times 1\times 1.6\times {10}^{-19}}{{10}^{-20}}=\frac{14.4\times {10}^{9-19+20}}{1}=14.4\times {10}^{10}N/C \\ Regards \end{gathered}$$