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Elevation in Boiling Point

18 g of gluco...

Question

$18 g$ of glucose $(C_{6} H_{12} O_{6})$ is dissolved in $1 k g$ of water in a saucepan. At what temperature will the water boil at $1.013 b a r$ ?
[ $K_{b}$ for water is $0.52 K k g m o l^{- 1}$ ]

186.101

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100.090

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280.292

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373.202

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Solution

The correct option is B $100.090$
Given that
Weight of the glucose is 18g
Mass of the glucose is 180g
$K_{b}$ for water is $0.52 K k g / m o l$
As we know,
At 1 atm, the boiling point of water is 100 degree celcius.
$Δ T_{b} = \frac{(K_{b} \times wt of glucose)}{(wt of water \times GMW of glucose)}$
$Δ T_{b} = \frac{0.52 \times 18}{180 \times 1}$
$Δ T_{b} = \frac{9.36}{180}$
$Δ T_{b} = 0.052$
that implies
$T_{S} = 0.052 + 373.15 = 373.202$
$T_{S} = 373.202 K$
Therefore water boiling point is $373.202 K$

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Similar questions

18g of glucose $(C_{6} H_{12} O_{6})$ is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil (at 1 atm)? $K_{b}$ for water is $0.52 K k g m o l^{- 1}$ .

18 g

of glucose,

C_{6} H_{12} O_{6}

(Molar mass = 180 g

m o l^{- 1})

is dissolved in

1 k g

of water in a saucepan. At what temperature will this solution boil?
(

K_{b}

for water =

0.52 K k g m o l^{- 1}

, boiling points of pure water =

373.15 K

)

18 g

of glucose,

C_{6} H_{12} O_{6}

(Molar Mass

= 180 g / m o l

) is dissolved in

1 k g

of water in a sauce pan. At what temperature will this solution boil?

[K_{b}

for water

= 0.52 K k g m o l^{- 1}

, boiling point of pure water

= 373.15 K

]

Q. 18 g of glucose,

C_{6} H_{12} O_{6}

, is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil (1.013 bar pressure)?

K_{b}

for water is 0.52 K kg

m o l^{- 1}

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18 g of glucose (C6H12O6) is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil at 1.013 bar? [Kb for water is 0.52 K kg mol−1]

$18 g$ of glucose $(C_{6} H_{12} O_{6})$ is dissolved in $1 k g$ of water in a saucepan. At what temperature will the water boil at $1.013 b a r$ ?
[ $K_{b}$ for water is $0.52 K k g m o l^{- 1}$ ]