18 g of glucose (C₆H₁₂O₆) is present in 1000 g of an aqueous solution of glucose. The molality of this solution is:

0.1m

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0.5m

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1.1m

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Solution

The correct option is A
0.1m

18 g of glucose (C₆H₁₂O₆) is present in 1000 g of an aqueous solution of glucose. The molality of this solution is 0.1 M.

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18 g glucose $(C_{6} H_{12} O_{6})$ is added to 178.2 g water. The vapor presure of water (in torr) for this aqueous solution is:

(C_{6} H_{12} O_{6})

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