18gm of ice is converted into water at 0oC and 1 atm. The entropies of H2O(s) and H2O(I) are 38.2 and 60J/molK respectively. The enthalpy changes for this conversion is:
A
5951.4J/mol
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B
595.14J/mol
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C
−5951.4J/mol
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D
None of these
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Solution
The correct option is A5951.4J/mol Ice and water is eq. therefore ΔG=0 ΔG=ΔH−TΔS=0 S=S2−S1=60−38.2=21.83 H=273×21.83 H=5959.6Jm−1