18- There is uniform electric field in a region that is nbsp-E -8594-10NCi- Potential difference between points A-2-0-m and B-2-0-m is-1- nbsp-40 -160-Vm nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -2- nbsp-50 -160-Vm-3- nbsp-20 -160-Vm nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -4- nbsp-30 -160-Vm

Dear #160;student,position #160;vector #160;will #160;be #160;( 2 2)i^V=E #8594;.r #8594;V=10i^.( 2 2)i^V= 40VmRegards ...

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Byju's Answer

Standard IX

Physics

Current through a Wire

18. There is ...

Question

18. There is uniform electric field in a region that is $\vec{E} = 10 \frac{N}{C} \hat{i}$ . Potential difference between points A(2,0)m and B(-2,0)m is
(1) $- 40 \frac{V}{m}$ (2) $- 50 \frac{V}{m}$
(3) $- 20 \frac{V}{m}$ (4) $- 30 \frac{V}{m}$

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Solution

$D e a r s t u d e n t, p o s i t i o n v e c t o r w i l l b e (- 2 - 2) \hat{i} V = \vec{E} . \vec{r} V = 10 \hat{i} . (- 2 - 2) \hat{i} V = - 40 \frac{V}{m} R e g a r d s$

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18. There is uniform electric field in a region that is E→=10NCi^. Potential difference between points A(2,0)m and B(-2,0)m is (1) -40 Vm (2) -50 Vm (3) -20 Vm (4) -30 Vm

Dear student,position vector will be (-2-2)i^V=E→.r→V=10i^.(-2-2)i^V=-40VmRegards

18. There is uniform electric field in a region that is $\vec{E} = 10 \frac{N}{C} \hat{i}$ . Potential difference between points A(2,0)m and B(-2,0)m is
(1) $- 40 \frac{V}{m}$ (2) $- 50 \frac{V}{m}$
(3) $- 20 \frac{V}{m}$ (4) $- 30 \frac{V}{m}$

$D e a r s t u d e n t, p o s i t i o n v e c t o r w i l l b e (- 2 - 2) \hat{i} V = \vec{E} . \vec{r} V = 10 \hat{i} . (- 2 - 2) \hat{i} V = - 40 \frac{V}{m} R e g a r d s$