$18 \times 145 - 18 \times 45$

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Solution

$18 \times 145 - 18 \times 45 = 18 (145 - 45) = 18 \times 100 = 1800$

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If some moles of $O_{2}$ diffuses in 18 sec and same moles of other gas diffuses in 45 sec.Find the molecular weight of the unknown gas .

If some moles of $O_{2}$ diffuse in 18 sec and same moles of other gas diffuse in 45 sec then what is the molecular weight of the unknown gas

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