$180$ g of $30 % (w / w)$ $NaOH$ is prepared. Calculate the volume of water utilised if the density of water is $0.9 g / cc$ .

$130$ mL

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$140$ mL

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$125$ mL

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$135$ mL

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Solution

The correct option is B
$140$ mL

Explanation of the correct option:
$30 % (w / w)$ means $30$ g of $NaOH$ is present in $100$ g of solution.
So, in $180$ g of solution, the amount of $NaOH$ present is $\frac{30}{100} x 180 = 54$ g.
Therefore, the amount of water present = $180 - 54 = 126$ g.
Now, $1 cc = 1 mL$
Also, $Density = \frac{Mass}{Volume}$
⇒ $Volume = \frac{Mass}{Density}$
⇒ $Volume = \frac{126}{0.9} = 140 mL$
Thus, the volume of water utilised is $140$ mL.

Hence, the correct option is (B).

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180g of 30%(w/w) NaOH is prepared. Calculate the volume of water utilised if the density of water is 0.9g/cc.

$180$ g of $30 % (w / w)$ $NaOH$ is prepared. Calculate the volume of water utilised if the density of water is $0.9 g / cc$ .