180mL of a hydrocarbon diffuses through a porous membrane in 15 minutes while 120mL of SO2 under identical conditions diffuses in 20 minutes. What is the molecular mass of hydrocarbon?
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Solution
r1= rate of diffusion of hydrocarbon =18015mLmin−1 r2= rate of diffusion of SO2=12020mLmin−1 r1r2=MSO2M Thus, 18015120/20=√64M 2=√64M So, M=16