$18 a^{3} b^{3} c^{2} \div 6 a b c =$

$2 a^{2} b^{2} c$

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$3 a^{2} b^{2} c$

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$3 a^{2} b c$

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$3 a b c$

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Solution

The correct option is B
$3 a^{2} b^{2} c$

Given:

$18 a^{3} b^{3} c^{2} \div 6 a b c$

$= \frac{18 a^{3} b^{3} c^{2}}{6 a b c}$

$∵ \frac{a^{n}}{a^{m}} = a^{n - m}$

$\Rightarrow \frac{18}{6} \times a^{(3 - 1)} b^{(3 - 1)} c^{(2 - 1)}$

$= 3 a^{2} b^{2} c$

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