18g of steam is passed over 2g of Iron.H2O + Fe → H2 + Fe2O3 Which is the excessive reagent? [Fe = 55.85g]
H2O
First, balance the given reaction.
3H2O + 2Fe → 3H2 + Fe2O3
∴ 3 moles of H2O = 2 moles of Fe
3 × 18g = 2 × 55.85g
54g of H2O = 111.7g of Fe
∴18g of H2O=18×111.754=37.23g of Fe
∴ Iron is the limiting reagent and H2O is in excess