18g of steam is passed over 2 g of Iron- H 2 O - Fe - H 2- F e 2 O 3 Which is the excessive reagent- - Fe -55-85 g -A- H2B- F eC- Fe 2 O 3D- H2 O

The correct option is D First, balance the given reaction. 3H_2O + 2Fe → 3H_2 + Fe_2O_3 ∴ 3 moles of H_2O = 2 moles of Fe 3 × 18g = 2 × 55.85g 54g of H_2O = ...

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Byju's Answer

Standard X

Chemistry

Mole Concept

18g of steam ...

Question

18g of steam is passed over 2g of Iron. $H_{2} O + F e \to H_{2} + F e_{2} O_{3}$ Which is the excessive reagent? [Fe = 55.85g]

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Solution

The correct option is A

First, balance the given reaction.

$3 H_{2} O + 2 F e \to 3 H_{2} + F e_{2} O_{3}$

$∴$ 3 moles of $H_{2} O$ = 2 moles of $F e$

$3 \times 18 g = 2 \times 55.85 g$

$54 g$ of $H_{2} O$ = $111.7 g$ of $F e$

$∴ 18 g o f H_{2} O = \frac{18 \times 111.7}{54} = 37.23 g o f F e$

$∴$ Iron is the limiting reagent and $H_{2} O$ is in excess

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Similar questions

18g of steam is passed over 2g of Iron. $H_{2} O + F e \to H_{2} + F e_{2} O_{3}$ Which is the excessive reagent? [Fe = 55.85g]

18 g

of steam is passed over

2 g

of iron.

H_{2} O + F e \to H_{2} + F e_{2} O_{3}

. is the excessive reagent? [Fe = 56 g]

$2 V O + 3 F e_{2} O_{3} \to 6 F e O + V_{2} O_{5}$ If we start with 2g of VO and 5.75g of $F e_{2} O_{3}$ , which is the limiting reagent?

[V = 47.87g] [Fe = 55.85g]

$2 V O + 3 F e_{2} O_{3} \to 6 F e O + V_{2} O_{5}$ If we start with 2g of VO and 5.75g of $F e_{2} O_{3}$ , which is the limiting reagent?

[V = 47.87g] [Fe = 55.85g]

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18g of steam is passed over 2g of Iron.H2O + Fe → H2 + Fe2O3 Which is the excessive reagent? [Fe = 55.85g]

The correct option is A First, balance the given reaction. 3H2O + 2Fe → 3H2 + Fe2O3 ∴ 3 moles of H2O = 2 moles of Fe 3 × 18g = 2 × 55.85g 54g of H2O = 111.7g of Fe ∴18g of H2O=18×111.754=37.23g of Fe ∴ Iron is the limiting reagent and H2O is in excess

18g of steam is passed over 2g of Iron. $H_{2} O + F e \to H_{2} + F e_{2} O_{3}$ Which is the excessive reagent? [Fe = 55.85g]