Question

$(19{)}^{29}\times (19{)}^{-27}=?$

• A. 6
• B. 361
• C. 19
• D. 6859
• E. None of these

Answer 1

Answer: (B)

361

Here, $(19{)}^{29}\times (19{)}^{-27}$
$[\because a^m\times a^n=a^{m+n}]$
$=(19{)}^{29-27}=(19{)}^2=361$