$19$ books weigh $11 k g 400 g$ . What is the weight of $21$ books ?

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Solution

Given, the weight of $19$ books $= 11 k g 400 g = 11.4 k g$ ( $∵ 1 k g = 1000 g$ )
Weight of $1$ book $= \frac{11.4 k g}{19} = 0.6 k g$
So, the weight of $21$ books $= 0.6 \times 21 = 12.6 k g = 12 k g 600 g$
Hence, the weight of $21$ books is $12 k g 600 g$ .

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