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Standard VII
Physics
Shear Modulus
19. Explain :...
Question
19. Explain :- A square lead slab of side 50cm and thickness 10cm is subject to a shearing force(on its narrow face) of 90000N.the lower edge is riveted to the floor.how much will the upper edge be displaced?
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Similar questions
Q.
A square shaped slab of lead with side
50
cm
and thickness
10.0
cm
is subjected to a shearing force (on its narrow face) of magnitude
9.0
×
10
4
N
. The lower edge is riveted to the floor as shown in figure. How much is the upper edge displaced, if the shear modulus of lead is
5.6
×
10
9
Pa
?
Q.
A square lead slab of side
50
c
m
and thickness
10
c
m
is subjected to a shearing force (on its narrow face) of
9
×
10
4
N
. The lower edge is riveted to the floor. How much will the upper edge be displaced?
(Shear modulus of lead
=
5.6
×
10
−
9
N
m
−
2
)
Q.
A square shaped slab of lead with side
50
cm
and thickness
10.0
cm
is subjected to a shearing force (on its narrow face) of magnitude
9.0
×
10
4
N
. The lower edge is riveted to the floor as shown in figure. How much is the upper edge displaced, if the shear modulus of lead is
5.6
×
10
9
Pa
?
Q.
A square lead slab of side 50 cm and thinness 10 cm is subject to ashearing force (on its narrow face) of
4
×
10
4
N
as shown. Lower edge is
η
is
10
1
0
N
/
m
2
, then upper edge is displaced by
Q.
A square brass plate of side 1.0m and thickness 0.005m is subjected to a force F on its smaller opposite edges causing a displacement of 0.02 cm. If the shear modulus of brass is
0.4
×
10
11
N
/
m
2
the value of the force F is
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