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Stoichiometry

19 g of a mix...

Question

19 g of a mixture containing $N a H C O_{3}$ and $N a_{2} C O_{3}$ on complete heating liberated 1.12 L of $C O_{2}$ at STP. The weight of the remaining solid was 15.9 g. What is the weight (in g) of $N a_{2} C O_{3}$ in the mixture before heating?

8.4

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15.9

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10.6

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Solution

The correct option is D 10.6
$N a H C O_{3}$ can only produce $C O_{2}$ on heating of the given mixture as per following balanced equation:

$2 N a H C O_{3} ⟶ N a_{2} C O_{3} + H_{2} O + C O_{2}$

This equation reveals that 22.4 L $C O_{2}$ is produced from 2 moles $N a H C O_{3}$ .

So 1.12 L of $C O_{2}$ can be obtained from $\frac{168}{22.4} \times 1.12 = 8.4 g$ of $N a H C O_{3}$ .

So the weight of $N a_{2} C O_{3}$ in the mixture of 19 g before heating was $= 19 - 8.4 = 10.6 g$

Hence, option D is correct.

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