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Question

19g of water at 30 and 5g of ice at ˚−20C are mixed together in a calorimeter. What is the final temperature of the mixture? (Given specific heat of ice =0.5calg−1()−1 and latent heat of fusion of ice =80calg−1)

A
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B
5
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C
5
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D
10
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Solution

The correct option is C 5Let the final temperature of mixture be t.Heat lost by water in calories, H1=19×1×(30−t) =570−19tHeat taken by ice, H2=msiΔt+mL+mswt =5×(0.5)20+5×80+5×1×tAccording to principle of calorimetry, H1=H2 5×(0.5)×20+5×80+5t=570−19t⇒24t=570−450=120⇒t=5

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