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Question

19g of water at 30 and 5g of ice at ˚20C are mixed together in a calorimeter. What is the final temperature of the mixture? (Given specific heat of ice =0.5calg1()1 and latent heat of fusion of ice =80calg1)

A
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B
5
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C
5
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D
10
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Solution

The correct option is C 5
Let the final temperature of mixture be t.
Heat lost by water in calories,
H1=19×1×(30t)
=57019t
Heat taken by ice, H2=msiΔt+mL+mswt
=5×(0.5)20+5×80+5×1×t
According to principle of calorimetry,
H1=H2
5×(0.5)×20+5×80+5t=57019t
24t=570450=120
t=5

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