19 g of water at 30-C and 5 g of ice at -20-C are mixed together in a calorimeter- What is the final temperature in -C of the mixture- Given specific heat of ice is 0-5 cal-g-C and latent heat of fusion of ice -80 cal-g-

We know that: Q=mL, Q=msΔθ Given: m_1=19 g, θ_1=30^∘C, nbsp; nbsp; nbsp; s_1=1 cal/g^∘C , m_2=5 g, θ_2= 20^∘C, s_2=0.5 ca/g^∘C, L= 80 cal/g Let final ...

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Standard VI

Physics

Thermal Equilibrium

19 g of water...

Question

$19 g$ of water at $30^{\circ} C$ and $5 g$ of ice at $- 20^{\circ} C$ are mixed together in a calorimeter. What is the final temperature (in $^{\circ} C$ ) of the mixture? Given specific heat of ice is $0.5 c a l / g^{\circ} C$ and latent heat of fusion of ice $= 80 c a l / g$ .

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Solution

We know that: $Q = m L, Q = m s Δ θ$

Given: $m_{1} = 19 g, θ_{1} = 30^{\circ} C, s_{1} = 1 c a l / g^{\circ} C, m_{2} = 5 g, θ_{2} = - 20^{\circ} C, s_{2} = 0.5 c a / g^{\circ} C, L = 80 c a l / g$

Let final temperature of mixture be $θ$ .

Heat lost by water is absorbed by ice,
$m_{1} s_{1} (30 - θ) = m_{2} s_{2} [(0 - (- 20)] + m_{2} L + m_{2} s_{1} (θ - 0)$

$19 \times 1 \times (30 - θ) = 5 \times 0.5 \times [0 - (- 20)] + 5 \times 80 + 5 \times 1 \times (θ - 0)$

$570 - 19 θ = 50 + 400 + 5 θ$

$24 θ = 120$

$θ = 5^{\circ} C$

Final answer: $5^{\circ} C$

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Similar questions

Q. 5 g of water at

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and 5 g of ice at

- 20^{o} C

are mixed together in a calorimeter. What is the final temperature of the mixture. Given specific heat of ice

= 0.5 c a l g^{- 1} (^{o} C)^{- 1}

and latent heat of fusion of ice

= 80 c a l g^{- 1}

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g^{- 1 o} C^{- 1}

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Thermal Equilibrium

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19 g of water at 30∘C and 5 g of ice at −20∘C are mixed together in a calorimeter. What is the final temperature (in ∘C) of the mixture? Given specific heat of ice is 0.5 cal/g∘C and latent heat of fusion of ice =80 cal/g.

$19 g$ of water at $30^{\circ} C$ and $5 g$ of ice at $- 20^{\circ} C$ are mixed together in a calorimeter. What is the final temperature (in $^{\circ} C$ ) of the mixture? Given specific heat of ice is $0.5 c a l / g^{\circ} C$ and latent heat of fusion of ice $= 80 c a l / g$ .