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Byju's Answer
Standard VII
Mathematics
RHS Criteria for Congruency
19. In ΔABC, ...
Question
19. In ΔABC, Angle BAC = 90^°, AD is the bisector of angle BAC and DE is perpendicular to AC. Prove that - DE (AB+AC) = AB AC.
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Similar questions
Q.
In figure,
∠
B
A
C
=
90
o
, AD is its bisector. If DE
⊥
AC, Prove that
D
E
×
(
A
B
+
A
C
)
=
A
B
×
A
C
.
Q.
In given figure,
∠
B
A
C
=
90
0
, AD is its bisector. IF DE
⊥
AC, Prove that
D
E
×
(
A
B
+
A
C
)
=
A
B
×
A
C
Q.
In triangle
A
B
C
,
∠
B
A
C
=
90
∘
,
and
A
D
is its bisector. If
D
E
is drawn
⊥
A
C
, prove that
D
E
×
(
A
B
+
A
C
)
=
A
B
×
A
C
.
Q.
∠
B
A
C
=
90
o
, AD is its bisector. If
D
E
⊥
A
C
, prove that
D
E
×
(
A
B
+
A
C
)
=
A
B
×
A
C
Q.
In a
Δ
ABC,
∠
BAC
=
90
o
, AD is its bisector. If DE
⊥
AC, then DE
×
(AB
+
AC)
=
2AB
×
AC.
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