Question

19.The least resolvable angle by a telescope using objective of aperture 5mis nearly (wavelength =4000angstorm)------

Answer 1

Dear Student,

$$\begin{gathered} \lambda =4000\times {10}^{-10}m \\ aperturesize=5m \\ \theta =\frac{\lambda }{aperturesize} \\ \theta =\frac{4000\times {10}^{-10}}{5}=800\times {10}^{-10}rad \end{gathered}$$
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