Question

190.0 ml of $N_2$ was collected in a jar over water at some temperature, water level inside and outside the jar standing at the same height. If barometer reads 740 mm Hg and aqueous tenstion at the temperature of the experiment is 20 mm Hg, the volume of the gas at 1 atm pressure and at the same temperature would be ?

• A. 180.0 mL
• B. 185.0 mL
• C. 190.0 mL
• D. 195.0 mL

Answer 1

The correct option is A

180.0 mL

$P_1$ (dry gas) $P_{wetgas}$ - aqueous tension
$=740-20=720mm,V_1=190.0ml$
$P_2=1$ atm = 760 mm, $V_2=?$;
Apply $P_1{V}_1=P_2{V}_2$
$\Rightarrow V_2=\frac{190\times 720}{760}=180ml$