Question

193245Two candidates attempt to solve a quadratic of the form $x^2+px+q=0.$ One starts with a wrong value of $p$ and finds the roots to be $2$ and $6$. The other starts with a wrong value of $q$ and finds the roots to be $2$ and $-9$. Find the correct roots.

• A. $3,4$
• B. $-2,-5$
• C. $-3,-4$
• D. None of these

Answer 1

Answer: (C)

$-3,-4$

$q$ is true so that product of roots are $2\times 6=12$.
Again $p$ is true so the sum of the roots is $-7$

So correct equation is $x^2+7x+12=0$
Therefore the roots are $-3$ and $-4$