1
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Question

# 1g charcoal adsorbs 100mL of 0.5M CH3COOH to form a monolayer.As a result molarity of acetic acid reduces to 0.49M. what will be the surface area covered by each molecule of acetic acid ?Given that surface area of charcoal =3.01×102m2/g

A
2.5×1019m2
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B
5×1019m2
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C
1018m2
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D
2.0×1018m2
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Solution

## The correct option is B 5×10−19m2Initial m moles =100×0.5=50Final m moles =100×0.49=49∴ m moles of CH3COOH adsorbed =1=10−3 moles.No. of molecules adsorbed =6.02×1020Area occupied by each molecule =3.01×1026.02×1020=5×10−19m2

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