Question

$1g$ of metal carbonate neutralises completely $200mL$ of $0.1NHCl$. The equivalent weight of metal carbonate is:

• A. $25$
• B. $50$
• C. $100$
• D. $75$

Answer 1

The correct option is B $50$

Given:

Mass of Metal Carbonate, m= 1g

Volume of HCl solution ,V = 200 ml= 0.2 litres

Normality of HCl solution , N =0.1N

Solution:

Number of equivalents of HCl solution = N×V

$\Rightarrow N_{eq}=0.1\times 0.2$

$\Rightarrow N_{eq}=0.02$

$MC{O}_3+2HCl\to MC{l}_2+H_{2}O+C{O}_2$

$N_{eq}HCl=N_{eq}MC{O}_3$

$\Rightarrow \frac{WeightofMC{O}_3}{equivalentweightofMC{O}_3}=0.02$

$\Rightarrow \frac{1}{EquivalentweightofMC{O}_3}=0.02$

$\Rightarrow EquivalentweightofMC{O}_3=\frac{1}{0.02}$

$\Rightarrow EquivalentweightofMC{O}_3=50g$

Hence, the correct option is B.