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Question

1g of Mg atoms in the vapour phase absorbs 50.0kJ of energy. Find the composition of Mg2+ formed as a result of absorption of energy. IE1 and IE2 for Mg are 740 and 1450kJ mol1 respectively.

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Solution

mole of Mg=124
These mole of Mg will be converted to Mg+ and Mg2+. Energy consumed for the conversion of Mg into Mg+2 is 740 + 1450 =2190.
Let a mole of Mg+ are formed, then
a×740+(124a)×2190=50
a=0.02845
%ofMg+=0.028451/24×100=68.28
%ofMg+2=31.72

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