1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Raoult's Law
1gram of a ca...
Question
1gram of a carbonate (M2CO3) on treatment with excess HCl produces 0.01186 mole of CO2, the molar mass of M2CO3 in g mol-1 is
Open in App
Solution
Suggest Corrections
4
Similar questions
Q.
1 gram of a carbonate
(
M
2
C
O
3
)
on treatment with excess. HCl produces 0.01186 mole of
C
O
2
.
the molar mass of
M
2
C
O
3
in g
m
o
l
−
1
is: -
Q.
1 gram of a carbonate
(
M
2
C
O
3
)
on treatment with excess
H
C
l
produces 0.01186 mole of
C
O
2
the molar mass of
M
2
C
O
3
in g mole
−
1
is:
Q.
1 gram of a carbonate
(
M
2
C
O
3
)
on treatment with excess. HCl produces 0.01186 mole of
C
O
2
.
the molar mass of
M
2
C
O
3
in g
m
o
l
−
1
is: -
Q.
4 moles of
M
g
C
O
3
is reacted with 6 moles of HCl solution. Find the volume of
C
O
2
gas produced at STP.
M
g
C
O
3
+
2
H
C
l
→
M
g
C
l
2
+
C
O
2
+
H
2
O
Q.
18.4g mixture of
C
a
C
O
3
and
M
g
C
O
3
, on strongly heating gives 8.8g of
C
O
2
gas. Calculate mole percentage of
M
g
C
O
3
in the mixture.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Liquids in Liquids and Raoult's Law
CHEMISTRY
Watch in App
Explore more
Raoult's Law
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app