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Volume of Gases and Number of Moles

1L of CO 2 be...

Question

1L of $C O_{2}$ becomes 1.6L when passed through a red-hot charcoal(C), amount of $C O_{2}$ in the mixture will be

A

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B

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C

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D

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Solution

The correct option is D

Let 1L of C and $C O_{2}$ mixture contain x litres of $C O_{2}$
$C + C O_{2} ⟶ 2 C O$
Therefore, total volume=(1+x)litres.
1+x=1.6, or, x=0.6 litres.
Hence, $60 % o f C O_{2}$

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1L of a mixture of CO and $C O_{2}$ becomes 1.6L when passed through a red hot charcoal, $C O_{2}$ in the mixture

1L of a mixture of CO and $C O_{2}$ becomes 1.6L when passed through a red hot charcoal, $C O_{2}$ in the mixture

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