Question

$(2^0+4^{-1})\times 2^2$ is equal to

• A. $2$
• B. $5$
• C. $4$
• D. $3$

Answer 1

The correct option is B $5$

As we know that $a^{-b}$ is equal to $1/a^b$. Also, $p^0=1$

So, $(2^0+4^{-1})\times 2^2=(1+1/4)\times 2^2$

by using distributive law of multiplication , we get

$(2^0+4^{-1})\times 2^2=1\times 2^2+1/4\times 2^2$

$(2^0+4^{-1})\times 2^2=4+1/4\times 4$ (because $2^2=2\times 2=4$)

$(2^0+4^{-1})\times 2^2=4+1=5$