${((2)^{2})}^{2} \times (3^{3} \div 4^{2}) \div 3^{2}$ is equal to

True

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False

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\frac{12}{3}

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Solution

The correct option is A
True

${((2)^{2})}^{2} \times (3^{3} \div 4^{2}) \div 3^{2}$
$= 4^{2} \times \frac{27}{16} \times \frac{1}{9}$
$= 16 \times \frac{27}{16} \times \frac{1}{9}$
$= \frac{27}{9} = 3$

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