${((2)^{2})}^{2}$ × ( $3^{3}$ ÷ $4^{2}$ ) ÷ $3^{2}$ is equal to

True

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False

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Solution

The correct option is A
True

Using BODMAS rule,
${((2)^{2})}^{2}$ × ( $3^{3}$ ÷ $4^{2}$ ) ÷ $3^{2}$

= $4^{2}$ × ( $3^{3}$ ÷ $4^{2}$ ) ÷ $3^{2}$

= $4^{2}$ × ( $\frac{27}{16}$ ) ÷ $3^{2}$

= $16 \times \frac{\frac{27}{16}}{9}$

= $16 \times \frac{27}{16 \times 9}$

= $\frac{27}{9}$

= $3$

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