$2^{2} + 5 \times (6 + 8) - 7$
In the given expression, the term with exponents would be solved first.

True

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False

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Solution

The correct option is B False

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Similar questions

2^{2} + 5 \times (6 + 8) - 7

In the given expression, the term with exponents would be solved first.

Question 158(ii)

Find a single machine that will do the same job as the given hook-up.
$a (\times 2^{4})$ machine followed by $(\times {(\frac{1}{2})}^{2})$ machine.
Maya multiplied $(4^{2} \times 3^{2})$ by thinking about stretching machines.

Use Maya's idea to multiply $5^{3} \times 2^{3}$ .
Maya's idea is another product law of exponents.
Multiplying Expressions with the same Exponents
$a^{c} \times b^{c} = (a \times b)^{c}$
You can use this law with more than two expressions. If the exponents are the same, multiply the expressions by multiplying the bases and using the same exponent. e.g. $2^{8} \times 3^{8} \times 7^{8} = (2 \times 3 \times 7)^{8} = 42^{8}$ .

Q. Solve the given expression:

[(3 + 2)^{2} + (7 \times 3)] \div (6 \div 3) =

Q. Express the following with positive exponents:

\frac{7^{- 4}}{7^{- 6}}

Solve the given exponent:

\sqrt[4]{12} \times \sqrt[7]{6}

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22+5×(6+8)−7 In the given expression, the term with exponents would be solved first.

The correct option is B False

$2^{2} + 5 \times (6 + 8) - 7$
In the given expression, the term with exponents would be solved first.