Question

2.2 cu dm(decimeter cube) of brass is to be drawn into a cylindrical wire of diameter 0.50 cm. Find the length of the wire(in m).

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Answer 1

Volume of brass = 2.2 ${dm}^3$ = (2.2 × 10 × 10 × 10 ) ${cm}^3$ = 2200 ${cm}^3$ = 2200 ${cm}^3$ .

Let the required length of wire be x cm.

Then, its volume = ($\pi$ $r^{2}x$) ${cm}^3$ = 2200 ${cm}^3$

$\frac{22}{7}$ × 0.25 × 0.25 × x = 2200

x = 11200 cm = 112m.

Hence, the length of wire is 112m.