Question

2.2 $d{m}^3$ of lead is to be drawn into a cylindrical wire 0.50 cm in diameter. The length of the wire is

(a) 110 m (b) 112 m (c) 98 m (d) 124 m

Answer 1

$Volumeofwire=(2.2\times 10\times 10\times 10)c{m}^3=2200c{m}^3\frac{22}{7}\times 0.25\times 0.25\times h=2200h=\frac{2200\times 7}{22\times 0.25\times 0.25}=11200cm\therefore Lengthofwire=\frac{11200}{100}m=112m$