Question

2(2x+3)-10 < 6 (x-2)

Answer 1

Here 2(2x+3)-10 < 6 (x-2)

$\Rightarrow 4x+6-10<6x-12\Rightarrow 4x-4<6x-12$

$\Rightarrow 4x-6x<-12+4\Rightarrow -2x<-8$

Dividing both sides by -2, we have

$\frac{-2x}{-2}>\frac{-8}{-2}\Rightarrow x>4$

Thus the solution set is $(4,\infty ).$