$(2^{- 3})^{- 2}$ =

2^{6}

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2^{- 6}

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2^{- 5}

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2^{- 5}

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Solution

The correct option is A $2^{6}$
We know that $(a^{m})^{n} = a^{m n}$ where $a$ is a non-zero integer and $m$ and $n$ are any integers.
$∴ (2^{- 3})^{- 2} = 2^{- 3 \times - 2} = 2^{6}$

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