$(2^{3})^{- 3} is equal to$ .

2^{- 9}

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2^{- 1}

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2^{- 6}

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2^{0}

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Solution

The correct option is A $2^{- 9}$
By using law of exponent:
$(a^{m})^{n} = a^{m n}$ Here $a$ is called the base and $m, n$ are called the exponent. For Power of power exponents are multiplied if the base is same.
$∴$ $(2^{3})^{- 3} = 2^{- 9}$

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